Samsung Placement Papers 2026
Last Updated: March 2026
Samsung Placement Papers 2026 - Complete Preparation Guide
📋 Company Overview
Samsung is a South Korean multinational conglomerate headquartered in Samsung Town, Seoul. It is the largest South Korean chaebol and one of the world's largest producers of electronic devices. Samsung Electronics, the flagship subsidiary, is a global leader in smartphones, semiconductors, and consumer electronics.
Key Highlights:
- Founded: 1938 by Lee Byung-chul
- Headquarters: Suwon, South Korea
- Industry: Conglomerate (Electronics, Semiconductors, Displays)
- Employees: 270,000+ globally
- India Presence: Major R&D centers in Bangalore, Noida, and Delhi
Eligibility Criteria 2026
| Parameter | Requirement |
|---|---|
| Education | B.Tech/B.E (CS, IT, ECE, EEE, Mechanical) |
| Batch | 2024, 2025, 2026 |
| Minimum CGPA | 7.0/10 or 70% |
| Backlogs | No active backlogs |
| Age Limit | Generally no strict limit |
Samsung CTC for Freshers 2026
| Component | Amount (Approx.) |
|---|---|
| Base Salary | ₹12-18 LPA |
| Joining Bonus | ₹1-2 Lakhs |
| RSUs | Variable |
| Benefits | Health Insurance, Relocation |
| Total CTC | ₹14-22 LPA |
📝 Exam Pattern
Samsung's recruitment process typically consists of 3-4 rounds:
| Round | Duration | Questions | Topics |
|---|---|---|---|
| Aptitude Test | 60-75 mins | 60-70 | Quant, Logical, Verbal |
| Technical Test | 60 mins | 30-40 | CS Fundamentals, Coding |
| Coding Test | 60-90 mins | 2-3 | Data Structures, Algorithms |
| Technical Interview | 45-60 mins | - | Projects, Problem Solving |
| HR Interview | 30-45 mins | - | Behavioral, Culture Fit |
Marking Scheme:
- +1 for correct answer
- Negative marking varies (typically -0.25)
🧮 Aptitude Questions (15 with Solutions)
Question 1: Numbers
Find the unit digit of 4^102 × 9^51.
Solution: Unit digit of powers of 4 follows cycle: 4, 6, 4, 6...
- Even power → Unit digit = 6
- Odd power → Unit digit = 4
For 4^102: 102 is even, so unit digit = 6
Unit digit of powers of 9 follows cycle: 9, 1, 9, 1...
- Even power → Unit digit = 1
- Odd power → Unit digit = 9
For 9^51: 51 is odd, so unit digit = 9
Unit digit of product = 6 × 9 = 54 → Unit digit = 4
Question 2: Percentage
A number is increased by 20% and then decreased by 20%. What is the net change?
Solution: Shortcut formula: Net change = a + b + (ab/100) Where a = +20%, b = -20%
Net change = 20 - 20 + (20 × -20)/100 = 0 - 4 = -4% (decrease)
Question 3: Profit & Loss
A shopkeeper marks goods 40% above cost price and gives 25% discount. Find profit%.
Solution: Let CP = ₹100 Marked Price = 100 + 40% = ₹140 Selling Price = 140 - 25% of 140 = 140 - 35 = ₹105
Profit = 105 - 100 = ₹5 Profit% = 5%
Question 4: Time & Work
A can complete work in 12 days, B in 18 days. They work together for 4 days, then A leaves. How long will B take to complete remaining work?
Solution: A's 1 day work = 1/12 B's 1 day work = 1/18 Together in 4 days = 4 × (1/12 + 1/18) = 4 × (5/36) = 20/36 = 5/9
Remaining work = 1 - 5/9 = 4/9
Time for B to complete 4/9 work: = (4/9) ÷ (1/18) = (4/9) × 18 = 8 days
Question 5: Speed & Distance
A train 150m long crosses a platform 200m long in 35 seconds. Find speed in km/h.
Solution: Total distance = 150 + 200 = 350m Time = 35 seconds
Speed = 350/35 = 10 m/s Convert to km/h: 10 × 18/5 = 36 km/h
Question 6: Ratio & Proportion
If A:B = 3:4 and B:C = 5:6, find A:C.
Solution: A:B:C = 3×5 : 4×5 : 4×6 = 15:20:24
A:C = 15:24 = 5:8
Question 7: Averages
Average of 11 numbers is 50. Average of first 6 is 45, average of last 6 is 55. Find the 6th number.
Solution: Sum of 11 numbers = 11 × 50 = 550 Sum of first 6 = 6 × 45 = 270 Sum of last 6 = 6 × 55 = 330
6th number = (270 + 330) - 550 = 50
Question 8: Simple Interest
At what rate will ₹6000 amount to ₹8100 in 7 years at simple interest?
Solution: SI = 8100 - 6000 = ₹2100 Rate = (SI × 100)/(P × T) = (2100 × 100)/(6000 × 7) = 210000/42000 = 5%
Question 9: Compound Interest
The compound interest on a sum for 2 years at 10% per annum is ₹840. Find the sum.
Solution: CI = P[(1 + r/100)^n - 1] 840 = P[(1.1)^2 - 1] = P[1.21 - 1] = 0.21P
P = 840/0.21 = ₹4000
Question 10: Logical Reasoning - Series
Find the next term: 2, 6, 12, 20, 30, ?
Solution: Pattern: 1×2, 2×3, 3×4, 4×5, 5×6, ... Next term = 6 × 7 = 42
Question 11: Coding-Decoding
If COMPUTER is coded as RFUVQNPC, how is MEDICINE coded?
Solution: Pattern: Each letter shifted by +1, -1 alternately C→D(+1), O→N(-1), M→N(+1), P→O(-1)...
MEDICINE: M→N, E→D, D→E, I→H, C→D, I→H, N→O, E→D = NDEHDHOD
Question 12: Blood Relations
Pointing to a man, a woman said, "His mother is the only daughter of my mother." How is the woman related to the man?
Solution:
- Only daughter of woman's mother = Woman herself
- So the man's mother is the woman
- Woman is the mother of the man
Question 13: Direction Sense
A man walks 5km North, turns right and walks 3km, turns right and walks 5km. How far is he from start?
Solution: Visualizing: North 5km, East 3km, South 5km Final position: 3km East of start Distance = 3 km
Question 14: Pipes & Cisterns
Pipe A fills tank in 6 hours, Pipe B empties in 8 hours. If both open, when will tank fill?
Solution: Net filling in 1 hour = 1/6 - 1/8 = (4-3)/24 = 1/24 Time to fill = 24 hours
Question 15: Calendar
What day of the week was January 1, 2024?
Solution: Using odd days method: 2000 years = 0 odd days 23 years (2001-2023): 17 normal + 6 leap years = 17×1 + 6×2 = 29 odd days = 1 odd day Jan 1, 2024 = 1 odd day
Monday
💻 Technical/CS Questions (10 with Solutions)
Question 1: Data Structures
What is the time complexity of binary search?
Explanation: Binary search divides the search space in half each iteration, resulting in logarithmic time complexity.
Question 2: Operating Systems
What is a deadlock and what are the necessary conditions?
Four necessary conditions (Coffman conditions):
- Mutual Exclusion
- Hold and Wait
- No Preemption
- Circular Wait
Question 3: DBMS
Explain ACID properties in databases.
- Atomicity: All operations complete or none
- Consistency: Database remains in consistent state
- Isolation: Concurrent transactions don't interfere
- Durability: Committed data survives failures
Question 4: Networks
Difference between TCP and UDP.
| Feature | TCP | UDP |
|---|---|---|
| Connection | Connection-oriented | Connectionless |
| Reliability | Reliable | Unreliable |
| Speed | Slower | Faster |
| Use case | Web, Email | Streaming, Gaming |
| Ordering | Guaranteed | Not guaranteed |
Question 5: OOP
What are the four pillars of OOP?
- Encapsulation: Bundling data and methods
- Inheritance: Acquiring properties from parent class
- Polymorphism: Same interface, different implementations
- Abstraction: Hiding implementation details
Question 6: Algorithms
Difference between BFS and DFS.
| Feature | BFS | DFS |
|---|---|---|
| Data Structure | Queue | Stack |
| Memory | More (stores all nodes at level) | Less |
| Use case | Shortest path | Cycle detection, Topological sort |
| Completeness | Complete | May not find solution |
Question 7: Computer Architecture
What is cache memory and why is it used?
Levels: L1 (fastest, smallest), L2, L3
Question 8: C Programming
What is the output: printf("%d", sizeof('A')); in C?
Explanation: In C, character constants are of type int, not char. So 'A' takes integer size (typically 4 bytes).
Question 9: Data Structures
When should you use a hash table vs a tree?
- Fast lookup is priority (O(1))
- Order doesn't matter
- Memory is sufficient
Use Tree when:
- Need ordered data
- Range queries needed
- Need hierarchical structure
Question 10: System Design
What is load balancing?
- Round Robin
- Least Connections
- IP Hash
- Weighted algorithms
📝 Verbal/English Questions (10 with Solutions)
Question 1: Synonyms
Choose the word closest in meaning to "EPHEMERAL": a) Eternal b) Transient c) Permanent d) Stable
Explanation: Ephemeral means lasting for a very short time; transient has the same meaning.
Question 2: Antonyms
Opposite of "BENEVOLENT": a) Kind b) Malevolent c) Generous d) Friendly
Explanation: Benevolent means well-meaning and kindly; malevolent means having/showing a wish to do evil.
Question 3: Error Spotting
Identify the error: "Each of the students have completed their assignment."
Explanation: "Each" is singular, so verb should be "has completed".
Question 4: Sentence Completion
The company's profits have _______ steadily over the past year. a) declined b) declining c) decline d) been declining
Explanation: Present perfect continuous tense is needed for ongoing action.
Question 5: Para Jumbles
Arrange: (A) The device (B) was invented (C) by Thomas Edison (D) the light bulb
Question 6: Reading Comprehension
Passage: "Innovation is not just about creating new products. It involves rethinking existing processes..."
Question: What is the main idea? Answer: Innovation encompasses more than just product creation; it includes process improvement.
Question 7: Idioms
Meaning of "to bite the bullet": a) To eat quickly b) To face a difficult situation c) To complain d) To give up
Question 8: One Word Substitution
A person who knows many languages: a) Polyglot b) Linguist c) Bilingual d) Multilingual
Question 9: Active to Passive
Convert: "The manager approved the proposal."
Question 10: Analogy
Book : Reader :: Painting : ? a) Canvas b) Artist c) Viewer d) Brush
Explanation: A book is viewed by a reader; a painting is viewed by a viewer.
💻 Coding Questions (5 with Python Solutions)
Question 1: Array - Two Sum
Find two numbers in array that sum to target.
def two_sum(arr, target):
seen = {}
for i, num in enumerate(arr):
complement = target - num
if complement in seen:
return [seen[complement], i]
seen[num] = i
return []
# Example
print(two_sum([2, 7, 11, 15], 9)) # Output: [0, 1]
Time Complexity: O(n), Space Complexity: O(n)
Question 2: String - Reverse Words
Reverse words in a string while maintaining word order.
def reverse_words(s):
words = s.split()
reversed_words = [word[::-1] for word in words]
return ' '.join(reversed_words)
# Example
print(reverse_words("Hello World")) # Output: "olleH dlroW"
Time Complexity: O(n), Space Complexity: O(n)
Question 3: Linked List - Detect Cycle
Detect if linked list has a cycle using Floyd's algorithm.
class ListNode:
def __init__(self, val=0):
self.val = val
self.next = None
def has_cycle(head):
if not head or not head.next:
return False
slow = head
fast = head.next
while fast and fast.next:
if slow == fast:
return True
slow = slow.next
fast = fast.next.next
return False
Time Complexity: O(n), Space Complexity: O(1)
Question 4: Dynamic Programming - Fibonacci
Calculate nth Fibonacci number using DP.
def fibonacci(n):
if n <= 1:
return n
dp = [0] * (n + 1)
dp[1] = 1
for i in range(2, n + 1):
dp[i] = dp[i-1] + dp[i-2]
return dp[n]
# Space optimized version
def fibonacci_optimized(n):
if n <= 1:
return n
a, b = 0, 1
for _ in range(2, n + 1):
a, b = b, a + b
return b
print(fibonacci(10)) # Output: 55
Time Complexity: O(n), Space Complexity: O(1) for optimized
Question 5: Tree - Level Order Traversal
Print binary tree level by level.
from collections import deque
class TreeNode:
def __init__(self, val=0):
self.val = val
self.left = None
self.right = None
def level_order(root):
if not root:
return []
result = []
queue = deque([root])
while queue:
level_size = len(queue)
current_level = []
for _ in range(level_size):
node = queue.popleft()
current_level.append(node.val)
if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)
result.append(current_level)
return result
# Example usage
root = TreeNode(3)
root.left = TreeNode(9)
root.right = TreeNode(20)
root.right.left = TreeNode(15)
root.right.right = TreeNode(7)
print(level_order(root)) # Output: [[3], [9, 20], [15, 7]]
Time Complexity: O(n), Space Complexity: O(w) where w is max width
🎯 Interview Tips
Technical Interview Tips:
-
Master Data Structures: Focus on arrays, linked lists, trees, graphs, and hash maps. Know when to use each.
-
Practice Samsung-Specific Questions: Samsung frequently asks about binary trees, matrix problems, and bit manipulation.
-
Know Your Projects: Be ready to explain your projects in detail, including challenges faced and how you solved them.
-
C/C++ Proficiency: Samsung heavily uses C/C++. Be comfortable with pointers, memory management, and OOP concepts.
-
Semiconductor Basics: For hardware roles, understand digital electronics, microprocessors, and VLSI basics.
HR Interview Tips:
-
Research Samsung Products: Show genuine interest in their latest smartphones, semiconductors, and innovations.
-
Why Samsung? Prepare a compelling answer about why you want to join Samsung specifically.
❓ Frequently Asked Questions
Q1: What is the eligibility criteria for Samsung campus placement?
A: Students from CS, IT, ECE, EEE, and Mechanical branches with 7.0+ CGPA and no active backlogs are eligible.
Q2: Does Samsung allow off-campus applications?
A: Yes, Samsung conducts Samsung STAR (Samsung Test for Aptitude & Technical Recruitment) for off-campus hiring.
Q3: What programming languages should I focus on?
A: C, C++, Java, and Python. C/C++ is particularly important for Samsung.
Q4: How to prepare for Samsung technical test?
A: Focus on data structures, algorithms, OS concepts, DBMS, and object-oriented programming. Practice previous year questions.
Q5: What is Samsung PRISM program?
A: PRISM (Preparing and Inspiring Student Minds) is Samsung's R&D internship program for final/pre-final year students.
Best of luck with your Samsung placement preparation! ⚡